## Rate dependency

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Matthew Casillas 1C
Posts: 29
Joined: Fri Sep 28, 2018 12:21 am

### Rate dependency

Is the rate really only dependent on the reactants? Is that the scope of this class?

Jacob Bershatski 4C
Posts: 30
Joined: Fri Sep 28, 2018 12:21 am

### Re: Rate dependency

I think we only consider reactants because we are talking about the initial rate. At that point, there will be minimal products formed so the concentrations of products are not considered.

Hedi Zappacosta 1E
Posts: 66
Joined: Fri Sep 28, 2018 12:27 am

### Re: Rate dependency

We are looking at the limiting reactant, or the one that reacts more slowly

Philipp_V_Dis1K
Posts: 32
Joined: Fri Sep 28, 2018 12:20 am

### Re: Rate dependency

the rate depends on the reactants initially, over time the products will decompose back into reactants as they reach equilibrium, but initially it only matters on reactants (assuming temperature and all other factors are constant)

anthony_trieu2L
Posts: 60
Joined: Fri Sep 28, 2018 12:29 am

### Re: Rate dependency

Also remember to look at the order of the reactants. If there rate order of a reactant is zero, then it is not dependent on the concentration, but rather k.

Anand Narayan 1G
Posts: 61
Joined: Fri Sep 28, 2018 12:15 am

### Re: Rate dependency

We focus a lot on initial reactants, as that tells us about the initial rate.