## First order rxn graphs [ENDORSED]

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Miriam Sheetz 2B
Posts: 64
Joined: Fri Sep 28, 2018 12:25 am

### First order rxn graphs

How do the graphs differ among first, second, and zero order reactions?

Laura Gong 3H
Posts: 89
Joined: Fri Sep 28, 2018 12:26 am
Been upvoted: 1 time

### Re: First order rxn graphs

It differs in the Y axis.
Zero order is simply [A] vs time.
First order is ln[A] vs time.
Second order is 1/[A] vs time.

Jonathan Pai 2I
Posts: 121
Joined: Fri Sep 28, 2018 12:27 am

### Re: First order rxn graphs

They are all linear, but 0th is [A], 1st is ln[A], 2nd is 1/[A]. It is that way to linearize the graph, and second order have a positive k slope.

RachelCheung1A
Posts: 30
Joined: Fri Sep 28, 2018 12:19 am

### Re: First order rxn graphs

They all have time on the x axis
Zero order has [A] on the y axis and slope is -k
First order has ln[A] on the y and slope is also -k
Second order has 1/[A] on the y and slope is k

Nicolle Fernandez 1E
Posts: 56
Joined: Fri Sep 28, 2018 12:25 am
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### Re: First order rxn graphs  [ENDORSED]

Zero order is A v. time with a slope of -K
First order is ln A v. time with a slope of -K
Second order is 1/A v. time with a slope of K