## Rate law with 2 reactants

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Jaira_Murphy_2D
Posts: 31
Joined: Fri Apr 06, 2018 3:00 am

### Rate law with 2 reactants

What is the rate law if the reaction is in 1st order, but there are 2 reactants?

Fiona Jackson 1D
Posts: 30
Joined: Fri Sep 28, 2018 12:22 am

### Re: Rate law with 2 reactants

Hi! I think if there are two reactants and the reaction is first order, that means the reaction is not the mechanism and you have to do an experiment to see which reactant affect the overall rate.

josie 1C
Posts: 18
Joined: Fri Sep 28, 2018 12:19 am

### Re: Rate law with 2 reactants

one of the reactants is 0th order, so the rate only depends on the concentration of the other one. When you write the overall rate law, you only include the reactants with order>0.

Jeremiah Hutauruk
Posts: 67
Joined: Fri Sep 28, 2018 12:28 am

### Re: Rate law with 2 reactants

one reactant is zero order and one is in first order