## Graphs

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Jessica Helfond 2F
Posts: 60
Joined: Fri Sep 28, 2018 12:16 am

### Graphs

Why does the graph of time versus concentration need to be linear?

Steven Garcia 1H
Posts: 79
Joined: Fri Sep 28, 2018 12:16 am

### Re: Graphs

I think the concentration is decreasing at a certain rate (with a certain slope) based on the reaction's k constant over time.