Half life
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Half life
Where does the 0.693 come from in the half life equation for first order reactions. Will that value ever change? I just want to know where it comes from and why we use it.
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Re: Half life
Using the integrated rate law of the first order reactions: ln [A] = -k t + ln [A]o, you can solve for the half-life (t1/2) by setting [A]= (1/2)[A]o.
Eventually you get, t1/2 = ln(2)/k or 0.693/k.
Eventually you get, t1/2 = ln(2)/k or 0.693/k.
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