## 1st order decay?

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

FrankieClarke2C
Posts: 59
Joined: Fri Sep 28, 2018 12:28 am

### 1st order decay?

Are all First Order Reactions decay functions

Elle_Mendelson_2K
Posts: 72
Joined: Fri Sep 28, 2018 12:28 am

### Re: 1st order decay?

Yes because you’re reactants are decreasing and slope is negative

Matthew Tran 1H
Posts: 165
Joined: Fri Sep 28, 2018 12:16 am

### Re: 1st order decay?

Yes. If you raise e to the power of both sides of the integrated rate law, you will get $[A]=[A]_{0}e^{-kt}$, which is exponential decay. Keep in mind that this is with respect to reactant.