## Graph

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Rhea Shah 2F
Posts: 97
Joined: Thu Jul 25, 2019 12:17 am

### Graph

What should the graph of an ln reactant vs. time plot look like for first order reaction?

KarineKim2L
Posts: 100
Joined: Fri Aug 30, 2019 12:16 am

### Re: Graph

The graph should be linear if the reaction is first order.

Juliana Chopelas 1A
Posts: 50
Joined: Sat Aug 24, 2019 12:16 am

### Re: Graph

If the reaction is first order then the graph would be linear with a slope of -K. The same goes for zero and second order reactions. Their graphs should be linear.

805303639
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Joined: Thu Jul 11, 2019 12:16 am
Been upvoted: 1 time

### Re: Graph

Juliana Chopelas 1A wrote:If the reaction is first order then the graph would be linear with a slope of -K. The same goes for zero and second order reactions. Their graphs should be linear.

If the reaction is first order, then the plot of ln[A] vs time is linear and the slope equals -k. Similarly, for a zero order reaction, the plot of [A] vs time is linear with slope=-k. However, for a second order reaction, slope= +k for the linear plot of 1/[A] vs time.

905373636
Posts: 62
Joined: Thu Aug 01, 2019 12:15 am

### Re: Graph

If you write [A] vs. time for a 1st order run, though, it'll show exponential decay so make sure to have it in ln form!

pmokh14B
Posts: 107
Joined: Sat Aug 17, 2019 12:15 am

### Re: Graph

The graph should be a decreasing linear function.

nicole-2B
Posts: 103
Joined: Fri Aug 30, 2019 12:18 am

### Re: Graph

should look linear and have a negative slope which is -k

Joanne Lee 1J
Posts: 100
Joined: Thu Jul 25, 2019 12:15 am

### Re: Graph

If it is a first order reaction, the graph should be linear.

AKhanna_3H
Posts: 104
Joined: Wed Sep 18, 2019 12:19 am

### Re: Graph

The graph will be linear with a slope of -k

aishwarya_atmakuri
Posts: 101
Joined: Sat Jul 20, 2019 12:15 am

### Re: Graph

The graph will look linear and the slope is -k.