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Posted: Sun Mar 08, 2020 10:04 pm
by Ellen Amico 2L
How do you find the concentration of A in part c of this question?

It says:

Determine the rate constant for each of the following first- order reactions, in each case expressed for the rate of loss of A:
c) 2 A --> B + C
[A] initial = 0.153 M
and that after 115 s the concentration of B rises to 0.034 M.

Re: 7B.3

Posted: Sun Mar 08, 2020 10:11 pm
by nehashetty_2G
You just use stoichiometric relations to find the concentration of A. If 0.034M B was created, that means that two times that amount of A was used in creating B. Therefore, you subtract 0.068 from 0.153 to find [A]t (0.085M).

Re: 7B.3

Posted: Sun Mar 08, 2020 10:16 pm
by Niharika 1H
To find the concentration of A, you multiply (2molA/1molB) * (.034molB./L) to get 0.068 mol. Subtract this from the initial 0.153 to get 0.085