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Equilibrium constant and elementary reaction rate constants

Posted: Tue Mar 10, 2020 8:55 pm
by ShravanPatel2B
How is the equilibrium constant related to the forward and reverse rate constants of the
elementary reactions contributing to an overall reaction?

Re: Equilibrium constant and elementary reaction rate constants

Posted: Tue Mar 10, 2020 9:35 pm
by Jack Riley 4f
K=(k'/k) is the relationship between equilibrium constant and rate constants

Re: Equilibrium constant and elementary reaction rate constants

Posted: Tue Mar 10, 2020 9:37 pm
by Niharika 1H
The eq constant K = kf/kr.

Re: Equilibrium constant and elementary reaction rate constants

Posted: Wed Mar 11, 2020 12:42 am
by WYacob_2C
The equilibrium constant is equal to k(forward)/k(reverse). This is helpful when converting the concentration of intermediate species into concentrations of reactants of the overall reaction when given elementary reactions.

Re: Equilibrium constant and elementary reaction rate constants

Posted: Wed Mar 11, 2020 10:22 am
by Sartaj Bal 1J
For a forward reaction that is endothermic, increasing the equilibrium constant means that the forward rate constant will increase as well.

Re: Equilibrium constant and elementary reaction rate constants

Posted: Wed Mar 11, 2020 10:59 am
by Kevin Xu 4F
In an equilibrium reaction, there is a forward reaction and a reverse reaction happening at the same time. The forward reaction's rate can be modeled as rate=k[reactants] and the reverse reaction's rate can be modeled as rate = k'[products]. At equilibrium, since the rates of forward and reverse reactions are equal, you can set these equal to each other and rearrange the rate constants on one side to get k/k' = [products]/[reactants]