Outline 6: 7B) 13


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Alan Limones 1H
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Joined: Fri Sep 29, 2023 11:40 am

Outline 6: 7B) 13

Postby Alan Limones 1H » Fri Mar 15, 2024 11:08 pm

Hi, for this problem, I ended up with 15/(2.36x10^-2) but in the solutions textbook, they had 15/[(2.36x10^-2)x(.84)]but I am not sure why they multiply the concentration of A with the rate constant. I used the 2nd-order reaction equation, and then solved for t, but I did not end up with the concentration of A in the denominator like they did. So I am not sure if I did something wrong with my algebra or if I used the wrong equation.

Taryn 1J
Posts: 42
Joined: Wed Nov 15, 2023 9:19 am

Re: Outline 6: 7B) 13

Postby Taryn 1J » Fri Mar 15, 2024 11:57 pm

To my understanding, they just moved the "[A]0" term that was underneath 16/[A]0 - 1/[A]0. I believe that you would get the same answer if you solved the equation: (16/[A]0 - 1/[A]0)/k but they just wanted to simplify the amount of steps.


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