Achieve Question #5

[Maritza Jacobo]

Can someone explain how you do the second part of the question? I was able to do the first part of the question but I am stuck on the second half of the question. Thank you in advance!

[gary_vernes]

Which Achieve assignment is this for?

[Deep Mehta]

If [A] is tripled, you multiply the reaction rate by 3, and when [B] is halved, you are halfing it under the exponent, so (1/2)^2. Therefore, you multiply the rate by 1/4. So if you take the initial rate and multiply by 3, then multiply by 1/4, you get your answer.

[Azlyn Hernandez 2E]

Im guessing this is for this week's assignment.

Its almost the same as the 1st part, but you change the values and power them according to the rate law orders

Heres my work:

[Maleeha Amir 2E]

So the second part is asking what the initial rate would be when [A] is tripled and [b] is halved. Since A is first order, you would just multiply the inital rate by 3 (3 to the first power). Since B is second order, the change would be half to the second power so (1/2)^2 times the initial rate. So, you would multiple the initial rate by 3 and 0.5^2