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### Homework Problem 15.19

Posted: Sun Feb 19, 2017 10:37 pm
Hi guys,

I was doing question 15.19 and I was having trouble finding the order of the reaction of B. According to the solutions manual, the reaction is second order in B, but I don't understand what steps they took to get that answer so any clarification would be much appreciated. Thanks!

### Re: Homework Problem 15.19

Posted: Sun Feb 19, 2017 11:54 pm
Increasing the concentration of B by the ratio $\frac{3.02}{1.25}$ (from experiments 2 and 3) increases the rate by $\left ( \frac{3.02}{1.25} \right )^{2}$.

Therefore, the reaction is second order in B.

### Re: Homework Problem 15.19

Posted: Mon Feb 20, 2017 8:18 pm
I am also not understanding this part of the problem. The solution manual states that the rate is increased by (3.02/1.25)^2 however I am not seeing how the rate is increased by this amount.

Thank you!

### Re: Homework Problem 15.19

Posted: Thu Feb 23, 2017 4:17 pm
I believe that for problems where you can't easily recognize if the concentration is being doubled, etc. then you just use this ratio method. In this problem, the solution manual is observing experiments 2 and 3 that has concentrations, 1.25 and 3.02 respectively. It's really hard to tell what exactly happens from 1.25 to 3.02 to using the ratio of 3.02/1.25 is the easiest!