15.35


Moderators: Chem_Mod, Chem_Admin

Sabah Islam 1G
Posts: 50
Joined: Sat Jul 22, 2017 3:01 am

15.35

Postby Sabah Islam 1G » Sat Mar 03, 2018 2:54 pm

The solutions manual states that the equation for the half-life of a 2nd order reaction must be obtained, being [A]t=[A]0/1+[A]0*kt. How was this equation obtained/derived?

Vasiliki G Dis1C
Posts: 53
Joined: Fri Sep 29, 2017 7:04 am

Re: 15.35

Postby Vasiliki G Dis1C » Sat Mar 03, 2018 8:07 pm

The equation for the half-life of a second order reaction is t1/2=1/k[A]o. This is derived from the integrated rate law for a second order reaction. The equation is 1/[A]=kt+1/[A]o, and we know that at t=t1/2 [A]=1/2[A]o. Therefore, 1/[A]=2/[A]o. When you plug this into the equation, you get 2/[A]o=kt1/2 + 1/[A]o. You move the 1/[A]o to the other side and get kt1/2=1/[A]o, or t1/2=1/k[A]o. Hope this helps!


Return to “Second Order Reactions”

Who is online

Users browsing this forum: No registered users and 1 guest