Slope of second order reaction


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Carlos Gonzales 1H
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Joined: Fri Sep 29, 2017 7:05 am
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Slope of second order reaction

Postby Carlos Gonzales 1H » Sun Mar 04, 2018 2:14 pm

Why is the slope of a second order reaction positive compared to first and zero order reactions?

Annalise Eder 2L
Posts: 49
Joined: Sat Jul 22, 2017 3:01 am

Re: Slope of second order reaction

Postby Annalise Eder 2L » Sun Mar 04, 2018 2:21 pm

The variable for a second order reaction that create a linear graph are 1/[A] over time while for a first order reaction it is ln[A] over time and for a zero order reaction it is [A] over time. The 1/[A] creates a positive slope because as the concentration of A decreases 1/[A] increases.

Haocheng Zhang 2A
Posts: 52
Joined: Fri Sep 29, 2017 7:04 am

Re: Slope of second order reaction

Postby Haocheng Zhang 2A » Sun Mar 04, 2018 2:25 pm

For the second order reaction, k is proportional to 1/[A]. As the time of reaction increases, the concentration [A] decreases and 1/[A] increases, so the slope is positive.

Christy Zhao 1H
Posts: 50
Joined: Fri Sep 29, 2017 7:07 am

Re: Slope of second order reaction

Postby Christy Zhao 1H » Sun Mar 04, 2018 3:35 pm

The integrated rate laws of the zero and first-order have a -kt, while the second-order has a +kt. Since the integrated rate laws correspond to y=mx+c (m=k), the slope depends on k.


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