## Rate of consumption vs concentration

$\frac{d[R]}{dt}=-k[R]^{2}; \frac{1}{[R]}=kt + \frac{1}{[R]_{0}}; t_{\frac{1}{2}}=\frac{1}{k[R]_{0}}$

Megan Purl 1E
Posts: 49
Joined: Fri Sep 29, 2017 7:07 am

### Rate of consumption vs concentration

What would the graph for rate of consumption vs concentration look like for a second order reaction?

Priyanka Bhakta 1L
Posts: 50
Joined: Fri Sep 29, 2017 7:04 am

### Re: Rate of consumption vs concentration

I believe it would be sloping downwards I a curve, but it would be a less dramatic decrease with a more gradual decrease than an exponential decay curve.

Renee Delamater 2H
Posts: 31
Joined: Wed Nov 16, 2016 3:02 am

### Re: Rate of consumption vs concentration

why would it be a less dramatic decrease?