15.19


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Frenz Cabison 1B
Posts: 54
Joined: Fri Sep 29, 2017 7:07 am

15.19

Postby Frenz Cabison 1B » Mon Mar 05, 2018 5:13 pm

Can someone explain to me how the reaction is 2nd order in B?

Lena Nguyen 2H
Posts: 51
Joined: Fri Sep 29, 2017 7:06 am
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Re: 15.19

Postby Lena Nguyen 2H » Mon Mar 05, 2018 5:25 pm

We know that the reaction in B is second-order because increasing B by a factor (3.02/1.25) increases the rate by a factor (3.02/1.25)^2.

torieoishi1A
Posts: 32
Joined: Sat Jul 22, 2017 3:00 am

Re: 15.19

Postby torieoishi1A » Tue Mar 06, 2018 10:02 am

Compare rate 1&3 to find the order of concentration B because A conc and C conc remain constant between these two experiments.
Rate 3/rate 1=50.8/8.7=5.85
B conc3/B conc1=3.02/1.25=2.416
2.416^x=5.85
X=2
Therefore, the concentration B is a second order reaction.


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