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15.19

Posted: Mon Mar 05, 2018 5:13 pm
by Frenz Cabison 1B
Can someone explain to me how the reaction is 2nd order in B?

Re: 15.19

Posted: Mon Mar 05, 2018 5:25 pm
by Lena Nguyen 2H
We know that the reaction in B is second-order because increasing B by a factor (3.02/1.25) increases the rate by a factor (3.02/1.25)^2.

Re: 15.19

Posted: Tue Mar 06, 2018 10:02 am
by torieoishi1A
Compare rate 1&3 to find the order of concentration B because A conc and C conc remain constant between these two experiments.
Rate 3/rate 1=50.8/8.7=5.85
B conc3/B conc1=3.02/1.25=2.416
2.416^x=5.85
X=2
Therefore, the concentration B is a second order reaction.