Units of k for orders above 2nd

[Mary Becerra 2D]

So I noticed a trend with the units of k, we keep dividing each one by M (molarity) i.e. zero order is k M/s, first order is k 1/s, second order is k 1/M.s. Does this trend continue for 3rd, 4th, and 5th orders?

[Deap Bhandal L1 S1J]

Yes, for example, the k for a 10th order reaction would be M^(-9) * s^(-1).

[JamesAntonios 1E]

Yes this trend should continue. Just remember that for zero order, it is actually mol/l*s, not inverted.

[204918982]

Yes I'm pretty sure this will always work, I've never thought about it like this so thanks for the tip!

[Ilan Shavolian 1K]

isnt there supposed to be an L,L²... at the top??

[Fatima_Iqbal_2E]

A helpful way of finding the units for different orders is to use . The x value would be the order that you are finding your units for. For example, if you are trying to find the units for a 10th order reaction, it would be =. I hope this helps!

[Fatima_Iqbal_2E]

isnt there supposed to be an L,L²... at the top??

The M refers to molarity, so the liters would be implied. If m was written, then yes, L would've needed to have been specified.