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7th Edition 7A.11 2nd Order RXN

Posted: Thu Mar 07, 2019 9:25 pm
by abbydouglas1K
In this problem it says that these reactants react in a second order process so that k[H2][I2] is the rate. However I thought that a second order process was k[A]^2 . Does A just represent reactants and the square mean there is two reactants hence a second order process?

Re: 7th Edition 7A.11 2nd Order RXN

Posted: Thu Mar 07, 2019 9:54 pm
by Schuyler_Howell_4D
I think so. If you expanded it to be k[A][A] then you would be able to find that A could be two different reactants.

Re: 7th Edition 7A.11 2nd Order RXN

Posted: Sat Mar 09, 2019 5:34 pm
by Gracie Ge 2E
for a reaction with rate k[A]^a[B]^b, the order is simply a+b.
which means k[H2][I2] and a general k[A]^2 are both second order.