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2nd order

Posted: Sun Mar 10, 2019 10:18 pm
by Raquel Ruiz 1K
Can someone explain why a second order graph has a positive slope? Does this mean that the concentration is increasing?

Re: 2nd order

Posted: Mon Mar 11, 2019 1:08 am
by Ashley Kim
The second order graph has nothing to do with the concentration, but rather the second derivative.

Re: 2nd order

Posted: Mon Mar 11, 2019 2:16 am
by Maya_Peterson1C
The y-axis is the inverse of the concentration of A. Thus, the slope shows that as time increases, the inverse of [A] increases (not [A] itself).

Half-life qraphs

Posted: Mon Mar 11, 2019 2:33 am
by Priscilla Okaiteye
Do we also have to know or study the graphs for half-life?

Re: 2nd order

Posted: Mon Mar 11, 2019 4:10 pm
by Nicolle Fernandez 1E
Since the graph is 1/A v time and when you integrate that you'll get 1/[A] = kt + 1/[A]o, and when you plot 1/[A] against t you'll get a positive slope because k is positive