## amounts of reactant and its affect on rate

$\frac{d[R]}{dt}=-k[R]^{2}; \frac{1}{[R]}=kt + \frac{1}{[R]_{0}}; t_{\frac{1}{2}}=\frac{1}{k[R]_{0}}$

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CaminaB_1D
Posts: 63
Joined: Fri Sep 28, 2018 12:16 am

### amounts of reactant and its affect on rate

If a reaction is second order with respect to reactant A, if the concentration of reactant A is doubled, is the rate quadrupled?

StudentD2B
Posts: 43
Joined: Fri Sep 28, 2018 12:27 am

### Re: amounts of reactant and its affect on rate

Yes! exactly.
Zeroth order - Rate =k
First Order - Rate =k[A]
Second Oder - Rate =k[A]^2

A De Castro 14B 2H
Posts: 75
Joined: Fri Sep 28, 2018 12:29 am

### Re: amounts of reactant and its affect on rate

Yes, because the rate of that second order reaction is proportional to the squared value of reactant A. However, remember that this applies to reactions that only have one reactant. The overall order of the reaction would be different if there were more than one reactants.

daniella_knight1I
Posts: 57
Joined: Fri Sep 28, 2018 12:18 am

### Re: amounts of reactant and its affect on rate

Yes, that is correct.

Aiden Atoori 1C
Posts: 67
Joined: Fri Sep 28, 2018 12:24 am

### Re: amounts of reactant and its affect on rate

Yes that is exactly what happens! Good work!

Jack DeLeon 1B
Posts: 30
Joined: Fri Sep 28, 2018 12:20 am

### Re: amounts of reactant and its affect on rate

yes, and it all comes down the the ^2 in the rate equation of a second order reaction

Anand Narayan 1G
Posts: 61
Joined: Fri Sep 28, 2018 12:15 am

### Re: amounts of reactant and its affect on rate

Yes, that is precisely what happens.

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