rate
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Re: rate
The integrated rate law for a second-order reaction is
kt + 1/[A]o = 1/[A}
The graph has a positive k, straight line slope which means that over time concentration of A is increasing
For the general rate law, the units for K would be 1/(M * s)
kt + 1/[A]o = 1/[A}
The graph has a positive k, straight line slope which means that over time concentration of A is increasing
For the general rate law, the units for K would be 1/(M * s)
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Re: rate
Second order reactions have a graph of 1/(A) v time. If the reaction is second order, the graph would appear linear with k being +slope of the line.
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Re: rate
if we change a second order equations reactant by a factor, its rate will change by the factor^2
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