## rate

$\frac{d[R]}{dt}=-k[R]^{2}; \frac{1}{[R]}=kt + \frac{1}{[R]_{0}}; t_{\frac{1}{2}}=\frac{1}{k[R]_{0}}$

FrankieClarke2C
Posts: 59
Joined: Fri Sep 28, 2018 12:28 am

### rate

What is the relationship between the second order and it's rate?

Briana Lopez 4K
Posts: 44
Joined: Wed Nov 22, 2017 3:01 am

### Re: rate

The integrated rate law for a second-order reaction is
kt + 1/[A]o = 1/[A}

The graph has a positive k, straight line slope which means that over time concentration of A is increasing

For the general rate law, the units for K would be 1/(M * s)

Juliana Chopelas 1A
Posts: 50
Joined: Sat Aug 24, 2019 12:16 am

### Re: rate

Second order reactions have a graph of 1/(A) v time. If the reaction is second order, the graph would appear linear with k being +slope of the line.

Joowon Seo 3A
Posts: 100
Joined: Sat Aug 24, 2019 12:17 am
Been upvoted: 1 time

### Re: rate

if we change a second order equations reactant by a factor, its rate will change by the factor^2