rate
Moderators: Chem_Mod, Chem_Admin
-
FrankieClarke2C
- Posts: 59
- Joined: Fri Sep 28, 2018 12:28 am
-
Briana Lopez 4K
- Posts: 44
- Joined: Wed Nov 22, 2017 3:01 am
Re: rate
The integrated rate law for a second-order reaction is
kt + 1/[A]o = 1/[A}
The graph has a positive k, straight line slope which means that over time concentration of A is increasing
For the general rate law, the units for K would be 1/(M * s)
kt + 1/[A]o = 1/[A}
The graph has a positive k, straight line slope which means that over time concentration of A is increasing
For the general rate law, the units for K would be 1/(M * s)
-
Juliana Chopelas 1A
- Posts: 50
- Joined: Sat Aug 24, 2019 12:16 am
Re: rate
Second order reactions have a graph of 1/(A) v time. If the reaction is second order, the graph would appear linear with k being +slope of the line.
-
Joowon Seo 3A
- Posts: 100
- Joined: Sat Aug 24, 2019 12:17 am
Re: rate
if we change a second order equations reactant by a factor, its rate will change by the factor^2
Return to “Second Order Reactions”
Who is online
Users browsing this forum: No registered users and 1 guest