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Postby FrankieClarke2C » Sun Mar 17, 2019 9:08 am

What is the relationship between the second order and it's rate?

Briana Lopez 4K
Posts: 44
Joined: Wed Nov 22, 2017 3:01 am

Re: rate

Postby Briana Lopez 4K » Sun Mar 17, 2019 9:33 am

The integrated rate law for a second-order reaction is
kt + 1/[A]o = 1/[A}

The graph has a positive k, straight line slope which means that over time concentration of A is increasing

For the general rate law, the units for K would be 1/(M * s)

Juliana Chopelas 1A
Posts: 50
Joined: Sat Aug 24, 2019 12:16 am

Re: rate

Postby Juliana Chopelas 1A » Sun Mar 01, 2020 11:14 pm

Second order reactions have a graph of 1/(A) v time. If the reaction is second order, the graph would appear linear with k being +slope of the line.

Joowon Seo 3A
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Re: rate

Postby Joowon Seo 3A » Tue Mar 03, 2020 9:04 am

if we change a second order equations reactant by a factor, its rate will change by the factor^2

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