## [A] v. Time

$\frac{d[R]}{dt}=-k[R]^{2}; \frac{1}{[R]}=kt + \frac{1}{[R]_{0}}; t_{\frac{1}{2}}=\frac{1}{k[R]_{0}}$

LNgo 1G
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Joined: Sat Aug 24, 2019 12:16 am

### [A] v. Time

For a first order reaction the [A] v Time plot is a decreasing exponential but what would the graph of [A] v Time look like for a second order reaction?

Haley Dveirin 1E
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### Re: [A] v. Time

For a second order reaction it gives a straight line.

Alfred Barrion 2H
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### Re: [A] v. Time

The graph of [A] v. Time would be linear.

Minh Ngo 4G
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### Re: [A] v. Time

Linear

Angela Patel 2J
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### Re: [A] v. Time

Would the slope of the graph be k?

805303639
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Been upvoted: 1 time

### Re: [A] v. Time

The graph of 1/[A] v Time for a second-order reaction yields a line with slope=k and y-intercept=1/[A]i. Hence the graph of [A] v Time for a second-order reaction would not be linear. The graph would be a rational function with a vertical asymptote at t= -1/(k[A]i).

nicole-2B
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### Re: [A] v. Time

Angela Patel 2J wrote:Would the slope of the graph be k?

yes the slope would be k

Shrayes Raman
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### Re: [A] v. Time

Linear 1/[A] v time but not [A] v time

Brandon Tao 1K
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### Re: [A] v. Time

The second order is linear

Jarrett Peyrefitte 2K
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### Re: [A] v. Time

It would be linear

Nawal Dandachi 1G
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### Re: [A] v. Time

for second order, it should be linear

JesseAuLec1Dis1G
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### Re: [A] v. Time

It's linear for second order. Does anyone know when it wouldn't be linear?

Caroline Zepecki
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Joined: Fri Aug 09, 2019 12:16 am

### Re: [A] v. Time

For a second order reaction, it would be linear.

McKenna_4A
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### Re: [A] v. Time

It would be linear, confirming that it is a 2nd order rxn.

Emily Vainberg 1D
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Joined: Sat Jul 20, 2019 12:15 am

### Re: [A] v. Time

If you look at the graoh of 1/[A] v Time for a second-order reaction, the slope is equal to K. The y intercept =1/[A]i. This means the graph for a second order reaction would be linear.

Jaci Glassick 2G
Posts: 104
Joined: Sat Jul 20, 2019 12:16 am

### Re: [A] v. Time

The slope of a 2nd order reaction (1/[A] vs. time) is k. The graph is linear.

Abigail Sanders 1E
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Joined: Wed Sep 11, 2019 12:16 am

### Re: [A] v. Time

The graph of [A] vs time would not be linear for a second order reaction. It is only linear for zero order. For second order the graph of 1/[A] vs t is a linear function with a slope equivalen to +k.