[A] v. Time


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LNgo 1G
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Joined: Sat Aug 24, 2019 12:16 am

[A] v. Time

Postby LNgo 1G » Tue Mar 03, 2020 11:38 am

For a first order reaction the [A] v Time plot is a decreasing exponential but what would the graph of [A] v Time look like for a second order reaction?

Haley Dveirin 1E
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Joined: Sat Jul 20, 2019 12:17 am

Re: [A] v. Time

Postby Haley Dveirin 1E » Tue Mar 03, 2020 11:41 am

For a second order reaction it gives a straight line.

Alfred Barrion 2H
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Re: [A] v. Time

Postby Alfred Barrion 2H » Tue Mar 03, 2020 12:30 pm

The graph of [A] v. Time would be linear.

Minh Ngo 4G
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Re: [A] v. Time

Postby Minh Ngo 4G » Tue Mar 03, 2020 12:56 pm

Linear

Angela Patel 2J
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Re: [A] v. Time

Postby Angela Patel 2J » Tue Mar 03, 2020 7:39 pm

Would the slope of the graph be k?

805303639
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Re: [A] v. Time

Postby 805303639 » Wed Mar 04, 2020 5:04 pm

The graph of 1/[A] v Time for a second-order reaction yields a line with slope=k and y-intercept=1/[A]i. Hence the graph of [A] v Time for a second-order reaction would not be linear. The graph would be a rational function with a vertical asymptote at t= -1/(k[A]i).

nicole-2B
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Joined: Fri Aug 30, 2019 12:18 am

Re: [A] v. Time

Postby nicole-2B » Wed Mar 04, 2020 10:40 pm

Angela Patel 2J wrote:Would the slope of the graph be k?

yes the slope would be k

Shrayes Raman
Posts: 129
Joined: Sat Jul 20, 2019 12:15 am

Re: [A] v. Time

Postby Shrayes Raman » Sun Mar 08, 2020 11:45 pm

Linear 1/[A] v time but not [A] v time

Brandon Tao 1K
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Re: [A] v. Time

Postby Brandon Tao 1K » Sun Mar 08, 2020 11:45 pm

The second order is linear

Jarrett Peyrefitte 2K
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Re: [A] v. Time

Postby Jarrett Peyrefitte 2K » Mon Mar 09, 2020 12:05 am

It would be linear

Nawal Dandachi 1G
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Re: [A] v. Time

Postby Nawal Dandachi 1G » Mon Mar 09, 2020 12:06 am

for second order, it should be linear

JesseAuLec1Dis1G
Posts: 52
Joined: Mon Jun 17, 2019 7:23 am

Re: [A] v. Time

Postby JesseAuLec1Dis1G » Mon Mar 09, 2020 12:54 am

It's linear for second order. Does anyone know when it wouldn't be linear?

Caroline Zepecki
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Re: [A] v. Time

Postby Caroline Zepecki » Tue Mar 10, 2020 11:55 am

For a second order reaction, it would be linear.

McKenna_4A
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Re: [A] v. Time

Postby McKenna_4A » Tue Mar 10, 2020 2:49 pm

It would be linear, confirming that it is a 2nd order rxn.

Emily Vainberg 1D
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Joined: Sat Jul 20, 2019 12:15 am

Re: [A] v. Time

Postby Emily Vainberg 1D » Wed Mar 11, 2020 10:40 am

If you look at the graoh of 1/[A] v Time for a second-order reaction, the slope is equal to K. The y intercept =1/[A]i. This means the graph for a second order reaction would be linear.

Jaci Glassick 2G
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Joined: Sat Jul 20, 2019 12:16 am

Re: [A] v. Time

Postby Jaci Glassick 2G » Wed Mar 11, 2020 10:48 am

The slope of a 2nd order reaction (1/[A] vs. time) is k. The graph is linear.

Abigail Sanders 1E
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Joined: Wed Sep 11, 2019 12:16 am

Re: [A] v. Time

Postby Abigail Sanders 1E » Wed Mar 11, 2020 12:16 pm

The graph of [A] vs time would not be linear for a second order reaction. It is only linear for zero order. For second order the graph of 1/[A] vs t is a linear function with a slope equivalen to +k.


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