how is a second order reaction related to a 2nd order integrated law?
Can someone explain each concept separately and how they are interconnected.
second order relation to second order integrated law
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Re: second order relation to second order integrated law
A second order reaction is a chemical reaction whose reaction rate is dictated by a second order integrated rate law. A second order integrated rate law is an expression which gives you the rate at which the second order reaction will proceed, and it is dependent on either the concentration of a single reactant raised to the second power, or the concentration of two different reactants raised to the first power. So the second order integrated rate law simply gives the rate of reaction for a second order reaction.
Re: second order relation to second order integrated law
For these second-order reactions, the integrated rate law is:
1/[A]=kt+1/[A]0
This equation relates the concentrations of reactants and the rate constant of second-order reactions.
1/[A]=kt+1/[A]0
This equation relates the concentrations of reactants and the rate constant of second-order reactions.
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Re: second order relation to second order integrated law
There is also a helpful page in the book for this which shows how the equation is derived. It is page 606.
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Re: second order relation to second order integrated law
If the second order rate is integrated, you end up with the second order rate law using a little calculus and algebra. The +C usually associated with an indefinite integral is represented in the integrated rate law by the initial concentration.
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Re: second order relation to second order integrated law
The second order reaction is derived from the second order integrated rate law, which is 1/[A]=kt+1/[A]0. This equation involves the concentrations as well as the rate constant of the second-order reaction.
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