Graphs

[Ellis Song 4I]

Can someone explain and summarize what the graphs for each order reaction looks like and what they mean?

[Tanmay Singhal 1H]

https://www.google.com/imgres?imgurl=ht ... mrc&uact=8




this image does a good job of graphing them. i believe it shows how one is related to the other and how fast it is used up

[Wendy 1E]

I suggest looking at the email that Dr. Lavelle sent us through email titled "Week 10 Review." It has the graphs for each order. Hope this helps!

[Michael Nguyen 1E]

A first-order reaction will have a straight-line graph of ln[A] v. t
A second-order reaction will have a straight-line graph of 1/[A] v. t
A zero-order reaction will have a straight-line graph of [A] v. t

The first-order and zero-order graphs will have negative slopes while the second-order graph will have a positive slope.

[Matt F]

The key to understanding the graphs is to look at the axis labels, especially if the plot is linear. As mentioned above, graphs of [A], ln[A], and 1/[A] vs t correspond to zero order, first order, and second order reactions when the plots are linear

[Juliana Chopelas 1A]

Zero order reaction: graph is concentration A v time, with a straight line where k is -slope
First order reaction: graph is ln of concentration A v time, with a straight line where k is -slope
Second Order reaction: graph is 1/concentration A v time, with a straight line where k is +slope

[Juliet Stephenson 4E]

Units of k also change for each order. Rate will always equal Moles/liter.seconds but since we are sometimes squaring or cubing concentration, K will have different units for each order. Most charts contain some reference to this.

[Emily Burghart 1k]

This is a good chart for reference.

[jessicasilverstein1F]

1st order: reaction will have a straight-line graph of ln[A] v. t
2nd order: reaction will have a straight-line graph of 1/[A] v. t
Zero order: reaction will have a straight-line graph of [A] v. t

Note that 1st and Zero have negative slope whereas 2nd is positive

[Brian Acevedo 2E]

I've attached a slide that hopefully summarizes everything pretty well. I hope this helps!