Graphs
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Graphs
Can someone explain and summarize what the graphs for each order reaction looks like and what they mean?
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Re: Graphs
https://www.google.com/imgres?imgurl=ht ... mrc&uact=8
this image does a good job of graphing them. i believe it shows how one is related to the other and how fast it is used up
this image does a good job of graphing them. i believe it shows how one is related to the other and how fast it is used up
Re: Graphs
I suggest looking at the email that Dr. Lavelle sent us through email titled "Week 10 Review." It has the graphs for each order. Hope this helps!
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Re: Graphs
A first-order reaction will have a straight-line graph of ln[A] v. t
A second-order reaction will have a straight-line graph of 1/[A] v. t
A zero-order reaction will have a straight-line graph of [A] v. t
The first-order and zero-order graphs will have negative slopes while the second-order graph will have a positive slope.
A second-order reaction will have a straight-line graph of 1/[A] v. t
A zero-order reaction will have a straight-line graph of [A] v. t
The first-order and zero-order graphs will have negative slopes while the second-order graph will have a positive slope.
Re: Graphs
The key to understanding the graphs is to look at the axis labels, especially if the plot is linear. As mentioned above, graphs of [A], ln[A], and 1/[A] vs t correspond to zero order, first order, and second order reactions when the plots are linear
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Re: Graphs
Zero order reaction: graph is concentration A v time, with a straight line where k is -slope
First order reaction: graph is ln of concentration A v time, with a straight line where k is -slope
Second Order reaction: graph is 1/concentration A v time, with a straight line where k is +slope
First order reaction: graph is ln of concentration A v time, with a straight line where k is -slope
Second Order reaction: graph is 1/concentration A v time, with a straight line where k is +slope
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Re: Graphs
Units of k also change for each order. Rate will always equal Moles/liter.seconds but since we are sometimes squaring or cubing concentration, K will have different units for each order. Most charts contain some reference to this.
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Re: Graphs
1st order: reaction will have a straight-line graph of ln[A] v. t
2nd order: reaction will have a straight-line graph of 1/[A] v. t
Zero order: reaction will have a straight-line graph of [A] v. t
Note that 1st and Zero have negative slope whereas 2nd is positive
2nd order: reaction will have a straight-line graph of 1/[A] v. t
Zero order: reaction will have a straight-line graph of [A] v. t
Note that 1st and Zero have negative slope whereas 2nd is positive
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Re: Graphs
I've attached a slide that hopefully summarizes everything pretty well. I hope this helps!
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