Wavelength
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Wavelength
You and a friend are tasked with the selection of a particular color for a laser pointer, but the one caveat is you must select a color that s both visible and non-damaging to the eyes in the scenario where the laser may land on someone's eye. what range of wavelengths would you want to use for this? Justify your answer with calculations
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Roma Patel 1K
- Posts: 43
- Joined: Fri Sep 27, 2024 7:16 am
Re: Wavelength
Not sure that this is within the scope of the class, but it's definitely an interesting question! Here is the explanation and corresponding calculations:
Green lasers (around 520–570 nm) are both highly visible and generally safe when used with low to moderate power, because of their high visibility and relatively low risk of harm when used responsibly.
Yellow-orange lasers (around 570–620 nm) are also visible and safer due to their lower energy compared to the shorter wavelengths.
E= ((6.626×10 ^-34)*(3.00×10^8))/(400×10 ^−9)
=4.97×10^−19 joules
E =((6.626×10^−34)*(3.00×10^8)/(570×10^−9)
=3.48×10^−19 joules
As we can see, the photon energy for 400 nm is higher than for 570 nm, indicating that shorter wavelengths (violet and blue) have more potential for causing damage.
Green lasers (around 520–570 nm) are both highly visible and generally safe when used with low to moderate power, because of their high visibility and relatively low risk of harm when used responsibly.
Yellow-orange lasers (around 570–620 nm) are also visible and safer due to their lower energy compared to the shorter wavelengths.
E= ((6.626×10 ^-34)*(3.00×10^8))/(400×10 ^−9)
=4.97×10^−19 joules
E =((6.626×10^−34)*(3.00×10^8)/(570×10^−9)
=3.48×10^−19 joules
As we can see, the photon energy for 400 nm is higher than for 570 nm, indicating that shorter wavelengths (violet and blue) have more potential for causing damage.
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