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Combining E=hv and c=ƛv

Posted: Sun Apr 15, 2018 11:45 pm
by Jose Lupian 1C
This past lecture Professor Lavelle showed an example where he combined E=hv and c=ƛv. This lead to the equation E=hc/ƛ. How did this combination result in this final equation?

Re: Combining E=hv and c=ƛv  [ENDORSED]

Posted: Mon Apr 16, 2018 12:40 pm
by Chem_Mod
Solve for v and plug v into E= hv.

Re: Combining E=hv and c=ƛv

Posted: Mon Apr 16, 2018 2:06 pm
by Isobel Tweedt 1E
v = c/ƛ so E = hc/ƛ

Re: Combining E=hv and c=ƛv

Posted: Wed Apr 18, 2018 8:07 pm
by Steven Luong 1E
So we have E = hv, where h is Planck's constant and v is the frequency. We have c = ƛv where ƛ is the wavelength, c is the speed of light while v is also frequency. If we solve for v in c = ƛv we will get v = c/ƛ. Now we can plug that into E = hv where we will get E = hc/ƛ.

Re: Combining E=hv and c=ƛv

Posted: Sun Apr 22, 2018 5:46 pm
by Elena 1H
from c=λv you solve for v and get v=c/λ. You substitute c/λ for v in the E=hv equation and get E=hc/λ

Re: Combining E=hv and c=ƛv

Posted: Sun Apr 22, 2018 9:47 pm
by Rummel Requerme 1E
First, you solve for v in the second equation, then plug that into E=hv.

Re: Combining E=hv and c=ƛv

Posted: Sun Oct 14, 2018 7:08 pm
by shouse1f
Will the value of c normally be given for use of the equation E=hc/ƛ?

Re: Combining E=hv and c=ƛv

Posted: Sun Oct 14, 2018 7:47 pm
by Alexandra Albers 1D
c is a constant, and it is likely that the value of it will be given to us in the equation sheet provided by Dr. Lavelle, but it might be useful to memorize it anyway.