6th Edition, Question 1.55


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Tyra Nguyen 4H
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Joined: Thu Sep 27, 2018 11:25 pm

6th Edition, Question 1.55

Postby Tyra Nguyen 4H » Wed Oct 24, 2018 3:13 pm

Anybody know how to do question 1.55, part c? The wording of the question is slightly confusing to me, where it says "absorbing at 3500 cm-1".

Te Jung Yang 4K
Posts: 51
Joined: Thu Sep 27, 2018 11:18 pm

Re: 6th Edition, Question 1.55

Postby Te Jung Yang 4K » Wed Oct 24, 2018 3:42 pm

It means to use the energy you got from part b of the exercise.
So, on the previous exercise, you would have for one absorbtion 7.2 * 10^-20J.
For the answer to part c, you would need to multiply that energy by Avogadro's constant.

Vanadium Wang 4H
Posts: 48
Joined: Thu Sep 27, 2018 11:19 pm

Re: 6th Edition, Question 1.55

Postby Vanadium Wang 4H » Sat Oct 27, 2018 9:40 pm

Using the method given above ^ you should get 4.3 x 10^4 J/mol or 43 kJ/mol


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