## 6th Edition, Question 1.55

$E=hv$

Tyra Nguyen 4H
Posts: 74
Joined: Fri Sep 28, 2018 12:25 am

### 6th Edition, Question 1.55

Anybody know how to do question 1.55, part c? The wording of the question is slightly confusing to me, where it says "absorbing at 3500 cm-1".

Te Jung Yang 4K
Posts: 63
Joined: Fri Sep 28, 2018 12:18 am

### Re: 6th Edition, Question 1.55

It means to use the energy you got from part b of the exercise.
So, on the previous exercise, you would have for one absorbtion 7.2 * 10^-20J.
For the answer to part c, you would need to multiply that energy by Avogadro's constant.

Posts: 60
Joined: Fri Sep 28, 2018 12:19 am

### Re: 6th Edition, Question 1.55

Using the method given above ^ you should get 4.3 x 10^4 J/mol or 43 kJ/mol

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