Changing equations

[RJ Lopez 2l]

I’m having a hard time trying to manipulate this equation I saw in the text book, could someone explain it pls

hv = work function = wavelength = ch/work function

[Tianle Zheng]

Is this the exact equation exhibited in the textbook? because I'm not quite sure if hv can equal lambda since frequency and wavelength are negatively related. However, I can try to help explain why ch/work function = lambda.
work function is hv

so ch/work function = lambda can be seen as

ch/hv = lambda
h can be eliminated, so the function turns to c/v = lambda, which could be transformed to c = v * lambda.

[almaortega]

Basically, what they did was combine the two equations c=lambda*nu and phi=h*nu by setting them equal to each other and manipulating the equation to solve for lambda. The nu's cancel out and you are left with lamba=ch/phi which helps solve for wavelength when the kinetic energy is 0.