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For part b of this question it asks for the rate law and the answer in the solutions manual says that the rate for step 2 equals k2[HBR][HOBR] however HOBR is an intermediate. I thought you weren't suppose to include the intermediate in the rate laws???
While the intermediate is part of rate 2, it is not the overall rate of the reaction. The intermediate is apart of the fast step 2, and we know that the slowest step determines the rate of the overall reaction. It is when the intermediate is apart of the overall rate that we must substitute it out.
KayleeMcCord1F wrote:What's an example of a situation when an intermediate would be considered in the overall rate law?
An intermediate would never be in the overall rate law. You would have to substitute it out using the pre-equilibirium approach.
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