## Mechanisms with equilbrium

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Jose_Arambulo_2I
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### Mechanisms with equilbrium

If you're given a two-step mechanism, where the first step is in a state of equilibrium, does that immediately make that step the fast step since pre equilbrium assumes that the equilibrium reaction comes before the slow step? Or do you have to compare the rate constants of each step to determine the rate determining step?

Chem_Mod
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### Re: Mechanisms with equilbrium

Jose_Arambulo_2I wrote:If you're given a two-step mechanism, where the first step is in a state of equilibrium, does that immediately make that step the fast step since pre equilbrium assumes that the equilibrium reaction comes before the slow step?

Correct

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