## Pre-Equilibrium approach

$K = \frac{k_{forward}}{k_{reverse}}$

Elle_Bertuccelli_1B
Posts: 24
Joined: Sat Jul 09, 2016 3:00 am

### Pre-Equilibrium approach

When the slow step comes before the fast step, can the pre-equilibrium approach still be used?

Khang_Tran_1O
Posts: 26
Joined: Fri Jul 22, 2016 3:00 am
Been upvoted: 1 time

### Re: Pre-Equilibrium approach

As Chem_mod replied in another post:

"You don't need to use the pre-equilibrium approach if the first step is a slow step. Remember, the slow step is the rate-determining step and a pre-equilibrium is when an intermediate is formed in a fast equilibrium reaction prior to a slow step in the mechanism."

So no, you don't need to use the approach in that case.