15.85

$K = \frac{k_{forward}}{k_{reverse}}$

Andy Liao 1B
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am

15.85

15.85 The following rate laws were each derived from an elementary reaction. In each case, write the chemical equation for the reaction, determine its molecularity, and draw a proposed structure for the activated complex:
(a) Rate = k[CH3CHO] (Products are CH3 and CHO.)
(b) Rate = k[I]2[Ar] (Products are I2 and Ar; the role of the Ar is to remove energy as the product forms.)
(c) Rate = k[O2][NO] (Products are NO2 and O.)

I understand how to write the chemical equation for the reaction and how to determine its molecularity, but can someone please explain how to draw a propose structure for the activated complex?

Andy Nguyen 1A
Posts: 56
Joined: Thu Jul 27, 2017 3:00 am

Re: 15.85

I think we did something like this in class today, but I found this link which had the same question. Hope this helps! viewtopic.php?t=2561