## Rate determining step

$K = \frac{k_{forward}}{k_{reverse}}$

Mike Matthews 1D
Posts: 59
Joined: Fri Sep 29, 2017 7:04 am

### Rate determining step

When deriving an overall rate law using pre-equilibrium approximation and a proposed mechanism, do we have to consider the rate determining step?

sahiltelang-Discussion 1J
Posts: 50
Joined: Thu Jul 13, 2017 3:00 am

### Re: Rate determining step

The pre-equilibria technique is regarding the balanced reaction equation and does not deal with the various elementary steps. Therefore, one does not need to worry about the slow step.

Alexia Joseph 2B
Posts: 56
Joined: Thu Jul 27, 2017 3:01 am

### Re: Rate determining step

When using the pre-equilibrium approach, you are trying to make sure that the proposed rate law is the same as the experimentally determined rate law. You use the pre-equilibrium approach to reason what the rate law for the equation is when the slow step has a reaction intermediate in it. By using the ratio of the rate constants at equilibrium to replace the concentration of the intermediate in terms of what you know, you can determine if the rate law for the slow step.