$K = \frac{k_{forward}}{k_{reverse}}$

Phi Phi Do 2E
Posts: 27
Joined: Fri Sep 29, 2017 7:05 am

What are the main differences between the steady state and pre-equilibrium approaches?

Oscar Beltran 3H
Posts: 6
Joined: Fri Jun 23, 2017 11:40 am

### Re: steady state vs. equilibrium

I think the main differences are that steady-state is more complicated and assumes that the intermediate concentration is low and constant whereas the pre equilibrium approach is easier to solve but with the restriction that the intermediate concentration has to be at equilibrium