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Rucha Kulkarni 2A
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Joined: Fri Sep 29, 2017 7:05 am


Postby Rucha Kulkarni 2A » Sun Mar 11, 2018 12:09 pm

Does anyone know how to solve exercise 15.71?

Srbui Azarapetian 2C
Posts: 54
Joined: Thu Jul 13, 2017 3:00 am
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Re: 15.71

Postby Srbui Azarapetian 2C » Sun Mar 11, 2018 9:37 pm

You basically solve this as you would a regular rate law with multiple steps. You cancel out the species/structures that are products in one equation and thus used as reactants in the others. These are your intermediates. The catalyst is not consumed in the reaction and is therefore present in the beginning and the end. In this case, it is the hydroxide ion. The intermediates that are cancelled out are RC(=N-)OH and RC(=NH)OH. This leaves the overall reaction of RCN+H2O yields RCONH2

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