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The Slow Step of a Reaction

Posted: Sun Mar 11, 2018 2:48 pm
by Ava Harvey 2B
I understand that the slow step of a reaction is the step that ultimately determines the overall rate and rate law. However, I was just wondering if the slow step in a reaction mechanism can ever be a step that is in equilibrium? Or are the fast steps the only ones that can be in equilibrium? Thanks so much!

Re: The Slow Step of a Reaction

Posted: Sun Mar 11, 2018 2:58 pm
by Aijun Zhang 1D
I think both slow step and fast step are not the overall step in the equilibrium.
The step in the equilibrium should be a combined step.

Re: The Slow Step of a Reaction

Posted: Sun Mar 11, 2018 3:18 pm
by Elizabeth Bamishaye 2I
From my understanding, fast steps are the only ones really that could be in equilibrium.