Page 1 of 1

15.89 reaction profile

Posted: Mon Mar 12, 2018 11:48 am
by Jessica Lutz 2E
The intermediate equations for the overall reaction, 2 NO(g) + 2 H2(g) -> N2(g) + 2 H2O(g) are:
Step 1: NO + NO -> N2O2
Step 2: N2O2 + H2 -> N2O + H2O
Step 3: N2O + H2 -> N2+ H2O
We determined that step 2 was the slow step and step 1 was at equilibrium. How do you estimate what the activation energy of step 3 is in the reaction profile?

Re: 15.89 reaction profile

Posted: Mon Mar 12, 2018 1:06 pm
by Joshua Xian 1D
We aren't given info on whether the activation energy for step 1 or step 3 is higher, so as long as both are different to each other and less than the activation energy for step 2, it should be ok.