## Intermediate

$K = \frac{k_{forward}}{k_{reverse}}$

lizzygaines1D
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am

### Intermediate

Can someone clarify how to determine if you have an intermediate or not?

Peri Bingham 1G
Posts: 50
Joined: Fri Sep 29, 2017 7:03 am

### Re: Intermediate

An intermediate is neither a reactant or a product. It is formed by the reactants in one step, and then reacts to form the products in another step.

Yutian Zhao -1J
Posts: 30
Joined: Fri Sep 29, 2017 7:05 am

### Re: Intermediate

An intermediate is a product in the former step and is consumed as a reactant in later step(s). And it won't show up in the overall reaction equation. Hope it helps.

Riya Pathare 2E
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### Re: Intermediate

I would just like to add that catalysts are "consumed" and "reproduced" but they are not intermediates. I think we have to be able to determine what are intermediates and what are catalysts.

Amanda Wu 2C
Posts: 31
Joined: Sat Jul 22, 2017 3:00 am

### Re: Intermediate

Both intermediates and catalysts don't show up in the overall net reaction. What distinguishes a catalyst from an intermediate is that a catalyst is there to begin with and becomes consumed (reactants side) in an elementary step only to be reformed again (products side) whereas an intermediate is formed in an elementary step (products side) only to be consumed in another elementary step (reactants side).

Harrison Wang 1H
Posts: 50
Joined: Fri Sep 29, 2017 7:07 am

### Re: Intermediate

Catalysts are involved in the first step of the equation on the reactants side and then reformed in another elementary step as products. Intermediates are formed during an elementary step first as products and then re-used as reactants later in another elementary step. Both do not show up in the overall equation.

Alejandra Rios 1L
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### Re: Intermediate

Intermediates can be identified when one of the products of a reaction is a reactant in a further step, meaning that the molecule was consumed. Also, the intermediates will not appear in the overall reaction.