15.89


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Tiffany Cao 1D
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Joined: Fri Sep 29, 2017 7:03 am
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15.89

Postby Tiffany Cao 1D » Mon Mar 12, 2018 11:46 pm

For #89, how do we know which step is the slow step when none of the rates match the experimental rate given?

Ammarah 2H
Posts: 30
Joined: Fri Sep 29, 2017 7:06 am

Re: 15.89

Postby Ammarah 2H » Tue Mar 13, 2018 12:05 am

You want to get the equations to match the given rate. So if you write the rate law for the second step, you'll notice that there is an intermediate in the rate (in this case, N2O2), and you do not want an intermediate in the final rate law. As a result, you look at the first step and write the rate law of the reverse reaction is equal to the forward rate, and divide to get [N2O2] by itself. You then plug that into the first rate law you wrote for step 2 and you'll notice that it matches the given rate law if k= k2 x (k1/k'1). Because this matches the given, you know that the second step has to be the slow step, since the slow step matches the given rate law.

Rakhi Ratanjee 1D
Posts: 59
Joined: Fri Sep 29, 2017 7:04 am

Re: 15.89

Postby Rakhi Ratanjee 1D » Tue Mar 13, 2018 12:58 am

Also, how do you know between Step 1 and Step 3 which step is faster?


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