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Postby RenuChepuru1L » Sat Mar 17, 2018 4:41 pm

Is rate of formation always the concentrations of the reactants of the rate determining step times k. also I didn't get what the solution was saying about second order

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Re: 15.51

Postby Christiana2D » Sat Mar 17, 2018 9:55 pm

Yes, the rate law is based on the rate determining step/slow step. It's second order because it depends on the concentrations of two different elements ([NO] and [Br2]) making it bimolecular.

Timothy Kim 1B
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Re: 15.51

Postby Timothy Kim 1B » Sat Mar 17, 2018 10:17 pm

would the unique rate for the formation of NOBr have a coefficient of 2?

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