## mechanism order

$K = \frac{k_{forward}}{k_{reverse}}$

Kassandra Molina 2B
Posts: 43
Joined: Wed Nov 16, 2016 3:03 am

### mechanism order

if a slow step is the first step and the fast step is the second in a mechanism, will the rate just be based on the first step or would you have to remove the intermediate and use k for a substitute in the second step?

juchung7
Posts: 44
Joined: Fri Sep 29, 2017 7:05 am

### Re: mechanism order

in this case, you would end up using the steady state approximation, since you can't have intermediates in your rate law.