mechanism order

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Kassandra Molina 2B
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Joined: Wed Nov 16, 2016 3:03 am

mechanism order

Postby Kassandra Molina 2B » Sun Mar 18, 2018 8:38 pm

if a slow step is the first step and the fast step is the second in a mechanism, will the rate just be based on the first step or would you have to remove the intermediate and use k for a substitute in the second step?

Posts: 44
Joined: Fri Sep 29, 2017 7:05 am

Re: mechanism order

Postby juchung7 » Mon Mar 19, 2018 12:17 am

in this case, you would end up using the steady state approximation, since you can't have intermediates in your rate law.

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