k1 and k2

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Carlos Gonzales 1H
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k1 and k2

Postby Carlos Gonzales 1H » Mon Mar 19, 2018 11:18 am

K can equal k1/k'1, but can it also equal k2/k'2? Is it just convention as to which step is the rate determining step?

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Re: k1 and k2

Postby Chem_Mod » Tue Mar 20, 2018 10:29 am

K would apply to any step at equilibrium.

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Re: k1 and k2

Postby AnuPanneerselvam1H » Wed Mar 21, 2018 6:59 am

K of reaction step 2 can equal k2/k'2. The equilibrium applies to all equations and is a ratio of forward rate reaction constant to reverse rate reaction constant.

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