## Pre-equilibrium reaction mechanisms

$K = \frac{k_{forward}}{k_{reverse}}$

Toru Fiberesima 1L
Posts: 63
Joined: Fri Apr 06, 2018 11:02 am

### Pre-equilibrium reaction mechanisms

What is meant by approximated concentrations for pre-equilibrium reaction mechanisms? How does this differ from the steady state? How are intermediates involved?

Elizabeth Gallmeister 1A
Posts: 41
Joined: Fri Sep 28, 2018 12:21 am

### Re: Pre-equilibrium reaction mechanisms

As we went over in lecture today, we can assume that the fast step preceding the rate-determining step is at an approximate equilibrium, because the product gets bottlenecked by the slow reaction. From there, we can use the K from the pre-equilibrium reaction in order to sub in values into the rate law of the slow step and get rid of any intermediates that may be in it. Steady state is another approach to doing this, but takes longer.

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