rate determining

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rate determining

Postby inlovewithchemistry » Tue Mar 12, 2019 6:40 pm

in deciding which of three steps is the rate determining step given the rate law, do you just match the given rate law to the reactants of one of the steps?
for example
step 1: NO + NO--> N2O2
step 2: N2O2 + H2 --> N2O + H2O
step 3: N2O + H2 --> N2 + H2O

rate= k[NO]^2[H2]

is step two the slow step just because the reactants match the given overall rate law?

Posts: 65
Joined: Fri Sep 28, 2018 12:17 am

Re: rate determining

Postby AdityaGuru1H » Tue Mar 12, 2019 6:49 pm

no in this case it would be because while step 2 may have been the determining step n2o2 was substituted by [no]^2 since n2o2 is not in the final equation. Only molecules that are in the overall reaction can be part of the rate law

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