## pre-equilibrium question

$K = \frac{k_{forward}}{k_{reverse}}$

Moderators: Chem_Mod, Chem_Admin

005199302
Posts: 108
Joined: Fri Sep 28, 2018 12:15 am

### pre-equilibrium question

If there are three steps in a reaction, two of which are fast, how do we know for which of the two to find K and substitute?

StudentD2B
Posts: 43
Joined: Fri Sep 28, 2018 12:27 am

### Re: pre-equilibrium question

Find K for the first fast step, If the fast step is after the slow step, (ie. fast, slow, fast) you can ignore the second fast step completely because steps that follow the rate determining step take place as soon as the intermediate has been formed and have a negligible effect on the overall rate

George Ghaly 2L
Posts: 66
Joined: Fri Sep 28, 2018 12:29 am
Been upvoted: 1 time

### Re: pre-equilibrium question

Only everything before the intermediate being formed contributes to the rate law so if it comes after the slow step it is not really accounted for.

Return to “Reaction Mechanisms, Reaction Profiles”

### Who is online

Users browsing this forum: No registered users and 2 guests