## exercise 15.65

$K = \frac{k_{forward}}{k_{reverse}}$

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### exercise 15.65

In this question, the equilibrium of the reaction is K=[B][C]/[A]^2
Should we consider the reaction order when calculating the equilibrium constant using rate constant?
Doesn't [A]^2 means the order of reaction for A is two? Why can we directly plug in the rate constants provided regardless of the reaction order?
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### Re: exercise 15.65

The equilibrium constant is defined as k/k', which is forward rate / reverse rate. The problem already gives you the rates, which already took into account the order with respect to reactants or products.